{"id":206,"date":"2016-12-19T21:06:49","date_gmt":"2016-12-19T21:06:49","guid":{"rendered":"http:\/\/rentabilitet.dk\/opgaver\/?page_id=206"},"modified":"2016-12-19T21:12:00","modified_gmt":"2016-12-19T21:12:00","slug":"plast-as","status":"publish","type":"page","link":"https:\/\/rentabilitet.dk\/opgaver\/virksomheds-oekonomi\/plast-as\/","title":{"rendered":"Plast A\/S"},"content":{"rendered":"<h1>Opgave 3<\/h1>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>3.1 (5 %)<\/strong><\/p>\n<p><strong>Beregn den optimale salgspris for produktet Y21. <\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>Jeg v\u00e6lger at benytte totalmetoden, hvor jeg ud fra tabellen i bilag 4 har beregnet oms\u00e6tning og d\u00e6kningsbidrag. Herefter har jeg s\u00e5 fundet den salgspris der giver det st\u00f8rste d\u00e6kningsbidrag, hvilket i dette tilf\u00e6lde er en salgspris p\u00e5 <u>3.650 kr.<\/u>.<\/p>\n<p>&nbsp;<\/p>\n<table width=\"492\">\n<tbody>\n<tr>\n<td width=\"95\"><strong>Salgspris<\/strong><\/td>\n<td width=\"95\"><strong>Afs\u00e6tning<\/strong><\/td>\n<td width=\"95\"><strong>Oms\u00e6tning<\/strong><\/td>\n<td width=\"107\"><strong>Variable omk.<\/strong><\/td>\n<td width=\"101\"><strong>DB i alt<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\"><strong>kr. <\/strong><\/td>\n<td width=\"95\"><strong>stk.<\/strong><\/td>\n<td width=\"95\"><strong>kr.<\/strong><\/td>\n<td width=\"107\"><strong>kr.<\/strong><\/td>\n<td width=\"101\"><strong>kr.<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.900<\/td>\n<td width=\"95\">3.200<\/td>\n<td width=\"95\">12.480.000<\/td>\n<td width=\"107\">4.381.440<\/td>\n<td width=\"101\">8.098.560<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.850<\/td>\n<td width=\"95\">3.300<\/td>\n<td width=\"95\">12.705.000<\/td>\n<td width=\"107\">4.524.960<\/td>\n<td width=\"101\">8.180.040<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.800<\/td>\n<td width=\"95\">3.400<\/td>\n<td width=\"95\">12.920.000<\/td>\n<td width=\"107\">4.674.320<\/td>\n<td width=\"101\">8.245.680<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.750<\/td>\n<td width=\"95\">3.500<\/td>\n<td width=\"95\">13.125.000<\/td>\n<td width=\"107\">4.830.000<\/td>\n<td width=\"101\">8.295.000<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.700<\/td>\n<td width=\"95\">3.600<\/td>\n<td width=\"95\">13.320.000<\/td>\n<td width=\"107\">4.992.480<\/td>\n<td width=\"101\">8.327.520<\/td>\n<\/tr>\n<tr>\n<td width=\"95\"><strong>3.650<\/strong><\/td>\n<td width=\"95\"><strong>3.700<\/strong><\/td>\n<td width=\"95\"><strong>13.505.000<\/strong><\/td>\n<td width=\"107\"><strong>5.162.240<\/strong><\/td>\n<td width=\"101\"><strong>8.342.760<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.600<\/td>\n<td width=\"95\">3.800<\/td>\n<td width=\"95\">13.680.000<\/td>\n<td width=\"107\">5.339.760<\/td>\n<td width=\"101\">8.340.240<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.550<\/td>\n<td width=\"95\">3.900<\/td>\n<td width=\"95\">13.845.000<\/td>\n<td width=\"107\">5.525.520<\/td>\n<td width=\"101\">8.319.480<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.500<\/td>\n<td width=\"95\">4.000<\/td>\n<td width=\"95\">14.000.000<\/td>\n<td width=\"107\">5.720.000<\/td>\n<td width=\"101\">8.280.000<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><strong>3.2 (5 %)<\/strong><\/p>\n<p><strong>Vurder, hvilken betydning det f\u00e5r for den optimale salgspris, hvis kvaliteten p\u00e5 Y21 \u00e6ndres efter kundernes \u00f8nske. Se sp\u00f8rgsm\u00e5l 3.1.<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>Her har jeg i hver enkelte r\u00e6kke lagt 300 gange den p\u00e5g\u00e6ldende afs\u00e6tning til de variable omkostninger, s\u00e5ledes at disse nu passer. Derefter har jeg p\u00e5 ny beregnet d\u00e6kningsbidraget, og det kan nu ses(i tabellen herunder), at den salgspris der nu giver det st\u00f8rste d\u00e6kningsbidrag er en salgspris p\u00e5 <u>3.700 kr<\/u>.<\/p>\n<p>&nbsp;<\/p>\n<table width=\"492\">\n<tbody>\n<tr>\n<td width=\"95\"><strong>Salgspris<\/strong><\/td>\n<td width=\"95\"><strong>Afs\u00e6tning<\/strong><\/td>\n<td width=\"95\"><strong>Oms\u00e6tning<\/strong><\/td>\n<td width=\"107\"><strong>Variable omk.<\/strong><\/td>\n<td width=\"101\"><strong>DB i alt<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\"><strong>kr. <\/strong><\/td>\n<td width=\"95\"><strong>stk.<\/strong><\/td>\n<td width=\"95\"><strong>kr.<\/strong><\/td>\n<td width=\"107\"><strong>kr.<\/strong><\/td>\n<td width=\"101\"><strong>kr.<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.900<\/td>\n<td width=\"95\">3.200<\/td>\n<td width=\"95\">12.480.000<\/td>\n<td width=\"107\">5.341.440<\/td>\n<td width=\"101\">7.138.560<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.850<\/td>\n<td width=\"95\">3.300<\/td>\n<td width=\"95\">12.705.000<\/td>\n<td width=\"107\">5.514.960<\/td>\n<td width=\"101\">7.190.040<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.800<\/td>\n<td width=\"95\">3.400<\/td>\n<td width=\"95\">12.920.000<\/td>\n<td width=\"107\">5.694.320<\/td>\n<td width=\"101\">7.225.680<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.750<\/td>\n<td width=\"95\">3.500<\/td>\n<td width=\"95\">13.125.000<\/td>\n<td width=\"107\">5.880.000<\/td>\n<td width=\"101\">7.245.000<\/td>\n<\/tr>\n<tr>\n<td width=\"95\"><strong>3.700<\/strong><\/td>\n<td width=\"95\"><strong>3.600<\/strong><\/td>\n<td width=\"95\"><strong>13.320.000<\/strong><\/td>\n<td width=\"107\"><strong>6.072.480<\/strong><\/td>\n<td width=\"101\"><strong>7.247.520<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.650<\/td>\n<td width=\"95\">3.700<\/td>\n<td width=\"95\">13.505.000<\/td>\n<td width=\"107\">6.272.240<\/td>\n<td width=\"101\">7.232.760<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.600<\/td>\n<td width=\"95\">3.800<\/td>\n<td width=\"95\">13.680.000<\/td>\n<td width=\"107\">6.479.760<\/td>\n<td width=\"101\">7.200.240<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.550<\/td>\n<td width=\"95\">3.900<\/td>\n<td width=\"95\">13.845.000<\/td>\n<td width=\"107\">6.695.520<\/td>\n<td width=\"101\">7.149.480<\/td>\n<\/tr>\n<tr>\n<td width=\"95\">3.500<\/td>\n<td width=\"95\">4.000<\/td>\n<td width=\"95\">14.000.000<\/td>\n<td width=\"107\">6.920.000<\/td>\n<td width=\"101\">7.080.000<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><strong>3.3 (5 %)<\/strong><\/p>\n<p><strong>Forklar, hvilken indflydelse Plast A\/S\u2019 kapacitetsomkostninger har p\u00e5 fasts\u00e6ttelsen af den optimale salgspris. <\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>Da virksomhedens kapacitetsomkostninger, som er p\u00e5 1.000.000, er konstante op til en produktion p\u00e5 4.000 stk., har disse ingen betydning, da det betyder at de ikke p\u00e5virker fasts\u00e6ttelsen af den optimale salgspris.<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<h1>Opgave 4<\/h1>\n<p>&nbsp;<\/p>\n<p><strong>4.1 (5 %)<\/strong><\/p>\n<p><strong>Vurder, hvilket lagerdisponeringssystem PL Import ApS anvender ved indk\u00f8b af G504.<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>PL Import k\u00f8ber ind efter bestillingspunkt. Det fungerer s\u00e5 s\u00e5ledes, at de hver gang deres lagerbeholdning kommer ned p\u00e5 100 tons, indk\u00f8ber 330 tons. Grunden til at de anvender dette system er, at leverand\u00f8ren ligger i Kina, hvilket giver lang transporttid samt dyre transport-omkostninger.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>4.2 (5 %)<\/strong><\/p>\n<p><strong>Vurder, om PL Import ApS indk\u00f8ber det optimale antal tons af G504 pr. gang.<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>De n\u00f8dvendige informationer fremg\u00e5r af bilag 5.<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p>Den optimale indk\u00f8bsst\u00f8rrelse beregner jeg ved hj\u00e6lp af Wilsons formel. Regnestykket kommer s\u00e5 til at se s\u00e5ledes ud:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-209\" src=\"http:\/\/rentabilitet.dk\/opgaver\/wp-content\/uploads\/2016\/12\/formel.jpg\" alt=\"\" width=\"302\" height=\"52\" srcset=\"https:\/\/rentabilitet.dk\/opgaver\/wp-content\/uploads\/2016\/12\/formel.jpg 302w, https:\/\/rentabilitet.dk\/opgaver\/wp-content\/uploads\/2016\/12\/formel-300x52.jpg 300w\" sizes=\"(max-width: 302px) 100vw, 302px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>Dvs. at det optimale indk\u00f8b pr. gang er 120 stk. Dermed indk\u00f8ber de alts\u00e5 v\u00e6sentlige mere pr. gang end de burde.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>4.3 (5 %)<\/strong><\/p>\n<p><strong>Beregn \u00e6ndringen i de \u00e5rlige lageromkostninger, hvis sikkerhedslageret \u00f8ges fra 60 tons til 100 tons.<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>Man skal finde ud af hvad det koster at have de ekstra 40 p\u00e5 lageret. Dette g\u00f8r man ved at gange dem med kostprisen, og s\u00e5 gange resultatet med renten.<\/p>\n<p>&nbsp;<\/p>\n<p>40 * 5.238 * 0,07 = <u>14.666,4<\/u><\/p>\n<p>&nbsp;<\/p>\n<p>Dvs. de \u00e5rlige lageromkostninger bliver for\u00f8get med kr. 14.666,40, hvis de \u00f8ger deres sikkerhedslager fra 60 tons til 100 tons.<\/p>\n<p>&nbsp;<\/p>\n\n","protected":false},"excerpt":{"rendered":"<p>Opgave 3 \u00a0 3.1 (5 %) Beregn den optimale salgspris for produktet Y21. &nbsp; Jeg v\u00e6lger at benytte totalmetoden, hvor jeg ud fra tabellen i bilag 4 har beregnet oms\u00e6tning og d\u00e6kningsbidrag. Herefter har jeg s\u00e5 fundet den salgspris der giver det st\u00f8rste d\u00e6kningsbidrag, hvilket i dette tilf\u00e6lde er en salgspris p\u00e5 3.650 kr.. &nbsp;<a class=\"moretag\" href=\"https:\/\/rentabilitet.dk\/opgaver\/virksomheds-oekonomi\/plast-as\/\"><span class=\"screen-reader-text\">L\u00e6s mere omPlast A\/S<\/span>[&#8230;]<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":26,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v16.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Plast A\/S - HHX opgaver og notater<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/rentabilitet.dk\/opgaver\/virksomheds-oekonomi\/plast-as\/\" \/>\n<meta property=\"og:locale\" content=\"da_DK\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Plast A\/S - HHX opgaver og notater\" \/>\n<meta property=\"og:description\" content=\"Opgave 3 \u00a0 3.1 (5 %) Beregn den optimale salgspris for produktet Y21. &nbsp; Jeg v\u00e6lger at benytte totalmetoden, hvor jeg ud fra tabellen i bilag 4 har beregnet oms\u00e6tning og d\u00e6kningsbidrag. 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